Joined

·
5 Posts

Slide 26 shows:

V Load = 900 lbs - coefficient of friction = 1.1

V Load = 1350 lbs - coefficient of friction = 1.05

V Load = 1800 lbs - coefficient of friction = 0.95

i.e. more load = less friction.

If the car has, say, 1350 lbs on each wheel then axle weight is 2 * 1350 lbs = 2700 lbs. The cornering force it can generate from the tyres is 1.05 * 1350 * 2 = 2835 lbs.

If there is a circumstance where one tyre has 900 lbs weight on it and the other has 1800, the cornering force it can generate is 1.1 * 900 + 0.95 * 1800 = 2700 lbs. 900 + 1800 is still 2700 lbs so the weight of the car hasn't changed at all, it's just more on one wheel than the other, which I think is what happens when a car goes round a corner.

So let me see:

Without weight transfer = 2835 lbs

With weight transfer = 2700 lbs

So if there were no weight transfer each axle could corner at 1.05 g. Which I think means the whole car can corner at 1.05 g? If there was weight transfer at both ends then the whole car could only corner at 1 g?

So is weight transfer bad for cornering? Is that why racing cars are always low?

If there was weight transfer at, say, the rear of the car then the rear axle could only corner at 1g and it would run out of friction first. I don't know if it's important which end of the car runs out of friction first, I usually drive very slowly. It feels like it might be important, though.

Of course I'm not an expert like Mycroft is. There might be something I'm missing. I would be really grateful if he could explain it to me and fill in the gaps, this all seems so complicated.

BBB